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Install NowVenkatesh
Nov 13, 2013
Yash Ukas
Jan 18, 2015
The values of
log 1 = 0
log 2 = 0.3010
log 3 = 0.4771
log 4 = 0.6020
log 5 = 0.6989
log 6 = 0.7781
...
Hyadarani
Apr 15, 2014
Let ‘a’ be any positive integer such that a = 3q +r, where 0 ≤ r < 6 and q is not equal to zero
Thus a= 3q, a= 3...
Rutul Thakkar
Feb 11, 2012
BAISHALI Rath
Apr 20, 2015
SANJAY Rohan Ravi
May 22, 2015
Krishna Bhakthochidan
Aug 20, 2013
Sir, Can you please solve the following:-
If the polynomial X4- 6X3+16X2-25X+10 is divided by another polynomial X2-2X+k, the reminder is X+a . Find k and a
Given that the remainder is (x + a)
⇒ (4k – 25 + 16 – 2k)x + [10 – k(8 – k) ] = x + a
⇒ (2k – 9)x + [10 – 8k + k<...
Anjali
Aug 26, 2013
Prove that. tan/1-cot+cot/1-tan=(1+sec cosec)
Ishita Gupta
Feb 27, 2015
Lavanya N
Nov 24, 2013
Venkatesh
Nov 13, 2013
Yash Ukas
Jan 18, 2015
The values of
log 1 = 0
log 2 = 0.3010
log 3 = 0.4771
log 4 = 0.6020
log 5 = 0.6989
log 6 = 0.7781
...
Hyadarani
Apr 15, 2014
Let ‘a’ be any positive integer such that a = 3q +r, where 0 ≤ r < 6 and q is not equal to zero
Thus a= 3q, a= 3...
Rutul Thakkar
Feb 11, 2012
BAISHALI Rath
Apr 20, 2015
SANJAY Rohan Ravi
May 22, 2015
Krishna Bhakthochidan
Aug 20, 2013
Sir, Can you please solve the following:-
If the polynomial X4- 6X3+16X2-25X+10 is divided by another polynomial X2-2X+k, the reminder is X+a . Find k and a
Given that the remainder is (x + a)
⇒ (4k – 25 + 16 – 2k)x + [10 – k(8 – k) ] = x + a
⇒ (2k – 9)x + [10 – 8k + k<...
Anjali
Aug 26, 2013
Prove that. tan/1-cot+cot/1-tan=(1+sec cosec)
Ishita Gupta
Feb 27, 2015
Lavanya N
Nov 24, 2013