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Venkatesh

Nov 13, 2013



Yash Ukas

Jan 18, 2015



Solution:
The values of
log 1 = 0
log 2 = 0.3010
log 3 = 0.4771
log 4 = 0.6020
log 5 = 0.6989
log 6 = 0.7781
...

Apr 15, 2014

#### Show that one and only one out of n,n+2,n+4 is divisible by 3, where n is any positive integer.



By Euclid division lemma:
Let ‘a’ be any positive integer such that  a = 3q +r,  where 0 ≤ r < 6 and q is not equal to zero
Thus a= 3q, a= 3...

BAISHALI Rath

Apr 20, 2015

#### Find the greatest 6 digits number exactly divisible by 24, 15,and 36.



Krishna Bhakthochidan

Aug 20, 2013

#### Sir, Can you please solve the following:- If the polynomial X4- 6X3+16X2-25X+10 is divided by another polynomial X2-2X+k, the reminder is X+a . Find k and a



Given that the remainder is (x + a)
⇒ (4k – 25 + 16 – 2k)x + [10 – k(8 – k) ] = x + a
⇒ (2k – 9)x + [10 – 8k + k<...

Lavanya N

Nov 24, 2013



Pragasam Ravi

May 22, 2015



P duraisami

Apr 28, 2014



Rutul Thakkar

Feb 11, 2012



Ishita Gupta

Feb 27, 2015



Venkatesh

Nov 13, 2013



Yash Ukas

Jan 18, 2015



Solution:
The values of
log 1 = 0
log 2 = 0.3010
log 3 = 0.4771
log 4 = 0.6020
log 5 = 0.6989
log 6 = 0.7781
...

Apr 15, 2014

#### Show that one and only one out of n,n+2,n+4 is divisible by 3, where n is any positive integer.



By Euclid division lemma:
Let ‘a’ be any positive integer such that  a = 3q +r,  where 0 ≤ r < 6 and q is not equal to zero
Thus a= 3q, a= 3...

BAISHALI Rath

Apr 20, 2015

#### Find the greatest 6 digits number exactly divisible by 24, 15,and 36.



Krishna Bhakthochidan

Aug 20, 2013

#### Sir, Can you please solve the following:- If the polynomial X4- 6X3+16X2-25X+10 is divided by another polynomial X2-2X+k, the reminder is X+a . Find k and a



Given that the remainder is (x + a)
⇒ (4k – 25 + 16 – 2k)x + [10 – k(8 – k) ] = x + a
⇒ (2k – 9)x + [10 – 8k + k<...

Lavanya N

Nov 24, 2013



Pragasam Ravi

May 22, 2015



P duraisami

Apr 28, 2014



Rutul Thakkar

Feb 11, 2012