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Yash Ukas

Jan 18, 2015

What are the values of log from 1 to 10?

The values of

log 1 = 0

log 2 = 0.3010

log 3 = 0.4771

log 4 = 0.6020

log 5 = 0.6989

log 6 = 0.7781

...

Hyadarani

Apr 15, 2014

Show that one and only one out of n,n+2,n+4 is divisible by 3, where n is any positive integer.

By Euclid division lemma:

Let â€˜aâ€™ be any positive integer such that a = 3q +r, where 0 â‰¤ r < 6 and q is not equal to zero

Thus a= 3q, a= 3...

Let â€˜aâ€™ be any positive integer such that a = 3q +r, where 0 â‰¤ r < 6 and q is not equal to zero

Thus a= 3q, a= 3...

BAISHALI Rath

Apr 20, 2015

Find the greatest 6 digits number exactly divisible by 24, 15,and 36.

This answer has an image. Please click on the question to read more.

Pragasam Ravi

May 22, 2015

Find the largest number which divide 615 and 963 leaving remainder 6 in each case.

This answer has an image. Please click on the question to read more.

Sparsh

Apr 27, 2015

Prove that the product of three consecutive positive integer is divisible by 6.

Answer.

Let us three consecutive integers be, n, n + 1 and n + 2.

Whenever a number is divided by 3 the remainder obtained is either 0 or 1 or 2.

let n = ...

Let us three consecutive integers be, n, n + 1 and n + 2.

Whenever a number is divided by 3 the remainder obtained is either 0 or 1 or 2.

let n = ...

Om Parkash

Sep 9, 2014

1] What is the smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case?

2] Determine the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8, 15 and 21.

3] A circular field has a circumfrence of 360 km. Three cyclists start together and can cycle 48 km, 60 km and 72 km a day, round the field. When will they meet again?

2] Determine the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8, 15 and 21.

3] A circular field has a circumfrence of 360 km. Three cyclists start together and can cycle 48 km, 60 km and 72 km a day, round the field. When will they meet again?

This answer has an image. Please click on the question to read more.

Preity Veronica

Aug 16, 2014

If 'n'is an odd positive integer, show that (n^{2}-1)^{ }Is divisible by 8??

Syed

Aug 26, 2013

Prove that if x and y are odd positive integers, then x^{2 }+ y^{2} is even but not divisible by 4

This answer has an image. Please click on the question to read more.

Nimmi Mary

Jul 16, 2013

A rectangular courtyard is 18m 72cm long and 13m 20cm broad. It is to be paved with square tiles of the same size. Find the leat possiable no. of such tiles.

Solution:

Given the dimensions of the rectangular courtyard:

Length = 18m 72cm = 1800 + 72 = 1872 cm

Breadth = 13m 20 cm = 1300 +20 cm = 1320 cm

In order to...

Given the dimensions of the rectangular courtyard:

Length = 18m 72cm = 1800 + 72 = 1872 cm

Breadth = 13m 20 cm = 1300 +20 cm = 1320 cm

In order to...

Daksh Mathur

Jul 18, 2009

Prove that the product of two consecutive positive integers is divisible by 2.

This answer has an image. Please click on the question to read more.

Yash Ukas

Jan 18, 2015

What are the values of log from 1 to 10?

The values of

log 1 = 0

log 2 = 0.3010

log 3 = 0.4771

log 4 = 0.6020

log 5 = 0.6989

log 6 = 0.7781

...

Hyadarani

Apr 15, 2014

Show that one and only one out of n,n+2,n+4 is divisible by 3, where n is any positive integer.

By Euclid division lemma:

Let â€˜aâ€™ be any positive integer such that a = 3q +r, where 0 â‰¤ r < 6 and q is not equal to zero

Thus a= 3q, a= 3...

Let â€˜aâ€™ be any positive integer such that a = 3q +r, where 0 â‰¤ r < 6 and q is not equal to zero

Thus a= 3q, a= 3...

BAISHALI Rath

Apr 20, 2015

Find the greatest 6 digits number exactly divisible by 24, 15,and 36.

This answer has an image. Please click on the question to read more.

Pragasam Ravi

May 22, 2015

Find the largest number which divide 615 and 963 leaving remainder 6 in each case.

This answer has an image. Please click on the question to read more.

Sparsh

Apr 27, 2015

Prove that the product of three consecutive positive integer is divisible by 6.

Answer.

Let us three consecutive integers be, n, n + 1 and n + 2.

Whenever a number is divided by 3 the remainder obtained is either 0 or 1 or 2.

let n = ...

Let us three consecutive integers be, n, n + 1 and n + 2.

Whenever a number is divided by 3 the remainder obtained is either 0 or 1 or 2.

let n = ...

Om Parkash

Sep 9, 2014

1] What is the smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case?

2] Determine the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8, 15 and 21.

3] A circular field has a circumfrence of 360 km. Three cyclists start together and can cycle 48 km, 60 km and 72 km a day, round the field. When will they meet again?

2] Determine the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8, 15 and 21.

3] A circular field has a circumfrence of 360 km. Three cyclists start together and can cycle 48 km, 60 km and 72 km a day, round the field. When will they meet again?

This answer has an image. Please click on the question to read more.

Preity Veronica

Aug 16, 2014

If 'n'is an odd positive integer, show that (n^{2}-1)^{ }Is divisible by 8??

Syed

Aug 26, 2013

Prove that if x and y are odd positive integers, then x^{2 }+ y^{2} is even but not divisible by 4

This answer has an image. Please click on the question to read more.

Nimmi Mary

Jul 16, 2013

A rectangular courtyard is 18m 72cm long and 13m 20cm broad. It is to be paved with square tiles of the same size. Find the leat possiable no. of such tiles.

Solution:

Given the dimensions of the rectangular courtyard:

Length = 18m 72cm = 1800 + 72 = 1872 cm

Breadth = 13m 20 cm = 1300 +20 cm = 1320 cm

In order to...

Given the dimensions of the rectangular courtyard:

Length = 18m 72cm = 1800 + 72 = 1872 cm

Breadth = 13m 20 cm = 1300 +20 cm = 1320 cm

In order to...

Daksh Mathur

Jul 18, 2009

Prove that the product of two consecutive positive integers is divisible by 2.

This answer has an image. Please click on the question to read more.