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Adarsh Nair

Feb 23, 2015

What is a ballistic galvanometer and what is its principle?

Answer.

A ballistic galvanometer is a galvanometer specially designed to measure the quantity of charge displaced in a current of short duration (such as in the chargin...

Answer (2)

Misha Jain

Sep 8, 2014

What is the work done by a magnetic field on a moving charge?

The work done by a uniform magnetic field on a moving charge is equal to zero. This is because the magnetic force is always perpendicular to velocity of the moving charge,

F

Answer (1)

Rizwana

May 21, 2015

What is right hand thumb rule?

This answer has an image. Please click on the question to read more.

Answer (1)

Misha Jain

Sep 9, 2014

Two identical charged particles moving with the same speed enter a region of uniform magnetic field. If one of these enters normal to the field direction and the other enters along a direction at 30° with the field, what would be the ratio of their angular frequencies?

Angular frequency ω = qB/m is independent of the angle at which the particle enters the magnetic field. Therefore the two identical particles will have the same angular frequency. So their angular fre...

Answer (1)

Anurag Verma

Jul 28, 2014

A closely wound soleniod 80 cm long has 5 layers of winding of 400 turns each. The diameter of the solenoid is 1.8 cm. If the current carried is 8.0 A, estimate the magnitude of magnetic field inside the solenoid near its centre.

This answer has an image. Please click on the question to read more.

Answer (1)

Mohammad Subhan

Jul 1, 2014

If a charged particle is thrown with a velocity v making an angle ø with magnetic field (ø is not equal to 90 degrees or 0 degrees) then i will travel helical motion due to magnetic force acting on the charged particle and due to the component of velocity along the direction of the magnetic field.But if we want to find the direction of resultant velocity of the charged particle at any instant during its helical motion then the magnitude of resultant velocity would be same as that of the velocity by which it thrown in the field(i.e v),but the direction of this speed (resultant velocity) at any instant of helical motion would be found by finding the resultant velocity vector of the horizontal component of velocity(along field) and the velocity component tangential at that point on the circular motion of charged particle.I WANT TO ONLY KNOW THAT IT IS CORRECT OR NOT??

The magnitude of the velocity at any instant is the same as v as the magnetic force does not change the velocity. But at every instant the direction of the velocity changes. As you said the direction of the (in...

Answer (1)

Arunima Ajan

Jun 25, 2014

What is the principle of cyclotron???

This answer has an image. Please click on the question to read more.

Answer (1)

Vidya

Sep 12, 2015

Considering the case of a parallel plate capacitor being charged show how one is required to generalise Amperes circuital law to include the term due to displacement current?

No answers yet.Be the first to answer

Answer (0)

Hemedra

Mar 25, 2015

Projectile motion

Let R be the horizontal range and H the maximum height and θ the angle of projection.

R = 2u2 sin θ ...

Answer (1)

Adarsh Nair

Feb 23, 2015

What is a ballistic galvanometer and what is its principle?

Answer.

A ballistic galvanometer is a galvanometer specially designed to measure the quantity of charge displaced in a current of short duration (such as in the chargin...

Answer (2)

Misha Jain

Sep 8, 2014

What is the work done by a magnetic field on a moving charge?

The work done by a uniform magnetic field on a moving charge is equal to zero. This is because the magnetic force is always perpendicular to velocity of the moving charge,

F

Answer (1)

Rizwana

May 21, 2015

What is right hand thumb rule?

This answer has an image. Please click on the question to read more.

Answer (1)

Misha Jain

Sep 9, 2014

Two identical charged particles moving with the same speed enter a region of uniform magnetic field. If one of these enters normal to the field direction and the other enters along a direction at 30° with the field, what would be the ratio of their angular frequencies?

Angular frequency ω = qB/m is independent of the angle at which the particle enters the magnetic field. Therefore the two identical particles will have the same angular frequency. So their angular fre...

Answer (1)

Anurag Verma

Jul 28, 2014

A closely wound soleniod 80 cm long has 5 layers of winding of 400 turns each. The diameter of the solenoid is 1.8 cm. If the current carried is 8.0 A, estimate the magnitude of magnetic field inside the solenoid near its centre.

This answer has an image. Please click on the question to read more.

Answer (1)

Mohammad Subhan

Jul 1, 2014

If a charged particle is thrown with a velocity v making an angle ø with magnetic field (ø is not equal to 90 degrees or 0 degrees) then i will travel helical motion due to magnetic force acting on the charged particle and due to the component of velocity along the direction of the magnetic field.But if we want to find the direction of resultant velocity of the charged particle at any instant during its helical motion then the magnitude of resultant velocity would be same as that of the velocity by which it thrown in the field(i.e v),but the direction of this speed (resultant velocity) at any instant of helical motion would be found by finding the resultant velocity vector of the horizontal component of velocity(along field) and the velocity component tangential at that point on the circular motion of charged particle.I WANT TO ONLY KNOW THAT IT IS CORRECT OR NOT??

The magnitude of the velocity at any instant is the same as v as the magnetic force does not change the velocity. But at every instant the direction of the velocity changes. As you said the direction of the (in...

Answer (1)

Arunima Ajan

Jun 25, 2014

What is the principle of cyclotron???

This answer has an image. Please click on the question to read more.

Answer (1)

Vidya

Sep 12, 2015

Considering the case of a parallel plate capacitor being charged show how one is required to generalise Amperes circuital law to include the term due to displacement current?

No answers yet.Be the first to answer

Answer (0)

Hemedra

Mar 25, 2015

Projectile motion

Let R be the horizontal range and H the maximum height and θ the angle of projection.

R = 2u2 sin θ ...

Answer (1)

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