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Asked by Neha Vilasi

Aug 19, 2013

If x +1 =3 , then find the value of x6+1.

x x6

x x6

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Asked by Raj kishore patro

Jul 10, 2013

x^{3} +__1/__x^{3 }= 110,then x+1/x =

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Asked by Meghna deshnur

Aug 5, 2013

Sir,

I have a doubt regarding this question, kindly tell me whether the answer for the question given below is correct?

Q) x^{3} - 3x^{2} - 9x - 5

Ans) p(x) = x^{3} - 3x^{2} - 9x - 5

Factors of 5 = 1,5,-1,-5

p(1) = 1^{3} - 3 x (1)^{2} - 9 x (1) - 5

= 1 -3 - 9 - 5

= 1 - 17 = - 16 â‰ 0

p(-1) = (-1)^{3} x 3 x (-1)^{2} - 9 x (-1) -5

= -1 - 3 + 9 - 5 = -9 + 9 = 0

p(-1) =0

âˆ´ (x+1) is a factor of p(x)

p(x) Ã· (x+1)

x^{3} - 3x^{2} - 9x - 5 Ã· x + 1

= x^{2 }- 4x - 5

x^{2} - 4x - 5

x^{2} - 5x + 1x - 5

= x ( x - 5) + 1 ( x - 5)

= ( x - 5) ( x + 1)

Yes you have done it correctly

Asked by Mohammed furqaan Hussain

Aug 23, 2013

If a2+b2+c2-ab-bc-ca=0,prove that a=b=c

Consider, a

Asked by Sunitha

Aug 19, 2013

Factorise: x4 +x2 +1

Consider x^{4} + x^{2} + 1

= (x^{4} + 2x^{2} + 1) â€“ x^{2}

&...

= (x

&...

Asked by Meghna deshnur

Jul 26, 2013

If x + y + z = 8 and xy + yz + zx = 20 find the value of x^{3} + y^{3} + z^{3} - 3xyz.

Answer.

Given x + y + z = 8 and xy + yz + zx = 20

Consider, x + y + z = 8

Squaring on both sides, we get

(x + y + z)2 = 82

x2 + y2 + z2 +2(xy + yz +zx) = 64

...

Given x + y + z = 8 and xy + yz + zx = 20

Consider, x + y + z = 8

Squaring on both sides, we get

(x + y + z)2 = 82

x2 + y2 + z2 +2(xy + yz +zx) = 64

...

Asked by Smritishraddha suresh

Aug 27, 2013

if x^{4}+1/x^{4 }=119 then find x^{3}-1/x^{3}

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Asked by Neha Vilasi

Aug 31, 2013

If a+b+c=0, then find the value of a2/bc+b2/ca+c2/ab and this time please explain it properly because last time I could not understand.

Given a + b + c = 0

Asked by Meghna deshnur

Jul 22, 2013

If a = 2 + âˆš3 then find the value of a - 1/a

Given a = 2 + âˆš3

Asked by Anshu

Oct 7, 2013

if 4^{x} - 4^{x - 1} = 24 then (2x)^{x }equals what ?

4^{X} - 4 ^{X-1} = 24

i.e., (2)^{2x} - (2)^{2(x -1)} = 24

i.e., (2)^{2x}

i.e., (2)

i.e., (2)