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Neha Vilasi

Aug 19, 2013

If x +1 =3 , then find the value of x6+1.

x x6

x x6

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Raj kishore patro

Jul 10, 2013

x^{3} +__1/__x^{3 }= 110,then x+1/x =

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Mohammed furqaan Hussain

Aug 23, 2013

If a2+b2+c2-ab-bc-ca=0,prove that a=b=c

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Meghna deshnur

Aug 5, 2013

Sir,

I have a doubt regarding this question, kindly tell me whether the answer for the question given below is correct?

Q) x^{3} - 3x^{2} - 9x - 5

Ans) p(x) = x^{3} - 3x^{2} - 9x - 5

Factors of 5 = 1,5,-1,-5

p(1) = 1^{3} - 3 x (1)^{2} - 9 x (1) - 5

= 1 -3 - 9 - 5

= 1 - 17 = - 16 â‰ 0

p(-1) = (-1)^{3} x 3 x (-1)^{2} - 9 x (-1) -5

= -1 - 3 + 9 - 5 = -9 + 9 = 0

p(-1) =0

âˆ´ (x+1) is a factor of p(x)

p(x) Ã· (x+1)

x^{3} - 3x^{2} - 9x - 5 Ã· x + 1

= x^{2 }- 4x - 5

x^{2} - 4x - 5

x^{2} - 5x + 1x - 5

= x ( x - 5) + 1 ( x - 5)

= ( x - 5) ( x + 1)

Yes, correct

But finally x^{3} - 3x^{2} - 9x - 5 = ( x + 1)( x + 1)( x - 5)

But finally x

Sunitha

Aug 19, 2013

Factorise: x4 +x2 +1

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Meghna deshnur

Jul 26, 2013

If x + y + z = 8 and xy + yz + zx = 20 find the value of x^{3} + y^{3} + z^{3} - 3xyz.

Answer.

Given x + y + z = 8 and xy + yz + zx = 20

Consider, x + y + z = 8

Squaring on both sides, we get

(x + y + z)2 = 82

x2 + y2 + z2 +2(xy + yz +zx) = 64

...

Given x + y + z = 8 and xy + yz + zx = 20

Consider, x + y + z = 8

Squaring on both sides, we get

(x + y + z)2 = 82

x2 + y2 + z2 +2(xy + yz +zx) = 64

...

Smritishraddha suresh

Aug 27, 2013

if x^{4}+1/x^{4 }=119 then find x^{3}-1/x^{3}

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Neha Vilasi

Aug 31, 2013

If a+b+c=0, then find the value of a2/bc+b2/ca+c2/ab and this time please explain it properly because last time I could not understand.

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Anshu

Oct 7, 2013

if 4^{x} - 4^{x - 1} = 24 then (2x)^{x }equals what ?

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Aakash Prakash

Sep 13, 2013

Prove that (a+b+c)^{3}-a^{3}-b^{3}-c^{3} = 3(a+b)(b+c)(c+a)

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Neha Vilasi

Aug 19, 2013

If x +1 =3 , then find the value of x6+1.

x x6

x x6

This answer has an image. Please click on the question to read more.

Raj kishore patro

Jul 10, 2013

x^{3} +__1/__x^{3 }= 110,then x+1/x =

This answer has an image. Please click on the question to read more.

Mohammed furqaan Hussain

Aug 23, 2013

If a2+b2+c2-ab-bc-ca=0,prove that a=b=c

This answer has an image. Please click on the question to read more.

Meghna deshnur

Aug 5, 2013

Sir,

I have a doubt regarding this question, kindly tell me whether the answer for the question given below is correct?

Q) x^{3} - 3x^{2} - 9x - 5

Ans) p(x) = x^{3} - 3x^{2} - 9x - 5

Factors of 5 = 1,5,-1,-5

p(1) = 1^{3} - 3 x (1)^{2} - 9 x (1) - 5

= 1 -3 - 9 - 5

= 1 - 17 = - 16 â‰ 0

p(-1) = (-1)^{3} x 3 x (-1)^{2} - 9 x (-1) -5

= -1 - 3 + 9 - 5 = -9 + 9 = 0

p(-1) =0

âˆ´ (x+1) is a factor of p(x)

p(x) Ã· (x+1)

x^{3} - 3x^{2} - 9x - 5 Ã· x + 1

= x^{2 }- 4x - 5

x^{2} - 4x - 5

x^{2} - 5x + 1x - 5

= x ( x - 5) + 1 ( x - 5)

= ( x - 5) ( x + 1)

Yes, correct

But finally x^{3} - 3x^{2} - 9x - 5 = ( x + 1)( x + 1)( x - 5)

But finally x

Sunitha

Aug 19, 2013

Factorise: x4 +x2 +1

This answer has an image. Please click on the question to read more.

Meghna deshnur

Jul 26, 2013

If x + y + z = 8 and xy + yz + zx = 20 find the value of x^{3} + y^{3} + z^{3} - 3xyz.

Answer.

Given x + y + z = 8 and xy + yz + zx = 20

Consider, x + y + z = 8

Squaring on both sides, we get

(x + y + z)2 = 82

x2 + y2 + z2 +2(xy + yz +zx) = 64

...

Given x + y + z = 8 and xy + yz + zx = 20

Consider, x + y + z = 8

Squaring on both sides, we get

(x + y + z)2 = 82

x2 + y2 + z2 +2(xy + yz +zx) = 64

...

Smritishraddha suresh

Aug 27, 2013

if x^{4}+1/x^{4 }=119 then find x^{3}-1/x^{3}

This answer has an image. Please click on the question to read more.

Neha Vilasi

Aug 31, 2013

If a+b+c=0, then find the value of a2/bc+b2/ca+c2/ab and this time please explain it properly because last time I could not understand.

This answer has an image. Please click on the question to read more.

Anshu

Oct 7, 2013

if 4^{x} - 4^{x - 1} = 24 then (2x)^{x }equals what ?

This answer has an image. Please click on the question to read more.

Aakash Prakash

Sep 13, 2013

Prove that (a+b+c)^{3}-a^{3}-b^{3}-c^{3} = 3(a+b)(b+c)(c+a)

This answer has an image. Please click on the question to read more.