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Asked by Keisam Robin

Oct 19, 2013

A solid iron rectangular block of dimensions 4.4 m, 2.6 m and 1 m

A solid iron rectangular block of dimensions 4.4 m, 2.6 m and 1 m is cast into a hollow cylindrical pipe of internal radius 30 cm and thickness 5 cm. Find the length of the pipe.

Answers(3)

Answer

Agam Gupta

Member since Sep 21, 2013

Internal radius, r = 30 cm
Thickness, w = 5 cm
External radius, R = 30 + 5 = 35 cm
Here volume of cuboid = volume of hollow cylinder
440 × 260 ×100 = π(R2 – r2)h
⇒ 440 × 260 × 100 = π(352 – 302)h
440 × 260 × 100 = π(325)h
h = 11200 cm = 112 m

Pranay Guda

Member since

Internal radius, r = 30 cm Thickness, w = 5 cm External radius, R = 30 + 5 = 35 cm Here volume of cuboid = volume of hollow cylinder 440 × 260 ×100 = π(R2 – r2)h ⇒ 440 × 260 × 100 = π(352 – 302)h ⇒ 440 × 260 × 100 = π(325)h ∴ h = 11200 cm = 112 m

Kishore Kumar

Member since

Internal radius, r = 30 cm
Thickness, w = 5 cm
External radius, R = 30 + 5 = 35 cm
Here volume of cuboid = volume of hollow cylinder
 440 × 260 ×100 = π(R2 – r2)h
⇒ 440 × 260  × 100 = π(352 – 302)h
 440  × 260 × 100 = π(325)h
∴ h = 11200 cm = 112 m
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