Q&A Forum
Get a free home demo of LearnNext

Available for CBSE, ICSE and State Board syllabus.
Call our LearnNext Expert on 1800 419 1234 (tollfree)
OR submit details below for a call back

clear

Asked by Reenasha

Sep 16, 2013

Explain how does an electric bell work.

Electric current and its effects

Answers(4)

Answer

Syeda

Member since Jan 25, 2017

Answer.

Electric current flows through the coil when the switch is ON, and the iron core acts as an electromagnet. The iron core attracts the hammer towards it. The hammer hits the bell and produces a sound. The circuit breaks at the screw contact when the hammer moves towards the iron core. At this point, the iron core ceases to be an electromagnet. The hammer is pulled back to its original position due to the spring action of the steel rod, and then touches the contact again to complete the circuit. The circuit is completed and current flows through the coil again, and the hammer strikes the bell again. The process repeats itself and you hear a ringing sound since the hammer keeps hitting the bell, until the switch is released.

Tanisha

Member since

When an armature or iron is in contact with screw the current flows though the coil which becomes an electromagnet .As,a result it gets pulled towards the magnet .The hammer at the end of the strip of the gong produce a sound .When electromagnet pulls and breaks the armature.The coil is no longer an electromagnet ,The armature touches the screw again which completes the circuit. This process is repeated in a quick succession.

Amarnathreddy M

Member since Jul 9, 2013

Construction and Working of an Electric Bell


An electric bell consists of an iron core, on which is wound a wire as a coil. One end of the coil is connected to one terminal of a battery, and the other end to a steel rod that acts like a spring for the hammer touching the screw contact. The other terminal of the battery is connected to the screw contact with a switch in the middle.


Working of an electric bell

Electric current flows through the coil when the switch is ON, and the iron core acts as an electromagnet. The iron core attracts the hammer towards it. The hammer hits the bell and produces a sound. The circuit breaks at the screw contact when the hammer moves towards the iron core. At this point, the iron core ceases to be an electromagnet. The hammer is pulled back to its original position due to the spring action of the steel rod, and then touches the contact again to complete the circuit. The circuit is completed and current flows through the coil again, and the hammer strikes the bell again. The process repeats itself and you hear a ringing sound since the hammer keeps hitting the bell, until the switch is released.

Refer to the following link for a good aniamation of working of an electric bell:
https://www.learnnext.com/CBSE-Class-VII-Science/Lesson-The-Magnetic-Effect-of-Electric-Current.htm

Asdfghjk

Member since

i know the answer but it is quiet a long one so I DONT HAVE THE TIME TO TYPE THE WHOLE ANSWER . But u can find the answer in the cbse science textbook class 7 .There u can find a clear answer to ur question .laugh
Like NextGurukul? Also explore our advanced self-learning solution LearnNext
Offered for classes 6-12, LearnNext is a popular self-learning solution for students who strive for excellence
Explore
Animated Video
lessons
All India
Test Series
Interactive Video
Experiments
Best-in class
books

Join India's most happening

Educational community