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Feb 4, 2015

# Three cubes each of side 5 cm are joined to the end. find the surface area of the resultant cuboid.

 Three cubes each of side 5 cm are joined to the end. find the surface area of the resultant cuboid.

Raghunath Reddy

Member since Apr 11, 2014

Sol: Given, each side of the cube is 5 cm. When three cubes are joined end to end, then the resulting solid is a cuboid. Length of the cuboid, l = 2 Ã— each side of the cube = 2 Ã— 5 cm = 10 cm Breadth of the cuboid, b = each side of the cube = 5 cm Height of the cuboid, h = each side of the cube = 5 cm Surface area of the cuboid = 2 (lb + bh + hl) = 2 (10 cm Ã— 5 cm + 5 cm Ã— 5 cm + 5 cm Ã— 10cm) = 2 (50 cm2 + 25cm2 + 50 cm2) = 2 Ã— 125 cm2. = 250 cm2. Thus, the surface area of the resulting cuboid is 250 cm2.

Rahul

Member since

It means joining three cubes length would be 15 nd b=5, h=5, Then calculate the surface area by using 2 (lb+bh+hl) formula
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