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Mihir Sharma

Dec 16, 2012

# A cuboidal tank has a length of 30 cm

A cuboidal tank has a length of 30cm, a breadth of 20cm and a height of 20cm.The tank is placed on a horizontal table and it is three-quarters full of water. Find the area of the tank which is in contact with water.

Syeda

Answer.     Height of tank in contact with water=3/4*20=15cm Area of four walls of tank in contact with water=2(l b)*h=2(30 20)*15=2*50*15=1500 sq. cm Area of base of tank in contact with water=l*b=30*20=600 sq. cm Therefore total area of tank in contact with water=(1500 600) sq. cm=2100 sq. cm

Shagufta

Height of tank in contact with water=3/4*20=15cmArea of four walls of tank in contact with water=2(l b)*h=2(30 20)*15=2*50*15=1500 sq. cmArea of base of tank in contact with water=l*b=30*20=600 sq. cmTherefore total area of tank in contact with water=(1500 600) sq. cm=2100 sq. cm

Kishore Kumar

Length (l), breadth (b) and height (h) of the cuboidal fish tank are 30 cm, 20 cm and 20 cm respectively. The area of the tank which is in contact with water   = Area of base of the cuboidal fish tank   = l  × b   = 30 cm × 20 cm    = 600 sq. cm

Member since Apr 1, 2017

Solution: Given dimensions of the cuboidal tank are Length = 30 cm Breadth = 20 cm Height = 20 cm  It is given three quarters full of water. So height of the water filled becomes three quarters of the the height of the tank    Height of water filled in a tank = ¾ x  20 = 15cm Area of tank that contact with water = Area of Bottom surface + Area of four walls that are contacting with water = lb + 2lh + 2bh  = 30 x  20 + 2 x 30 x 15 + 2 x 20 x 15 = 600 + 900 + 600 = 2100 sq.cm
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