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Gajaanan Muley

Nov 3, 2013

# An express train takes 1 hour less than a passenger train

An express train takes 1 hour less than a passenger train to travel 132 km/hr between Mysore and Bangalore.If the average speed of the express train is 11 km/hr more than that of passenger train,form an equation to find the average speed of the express train.

Kishore Kumar

Let the speed of passenger train be x km/hr Hence speed of express train = (x +11) km/hr Distance travelled by both the trains = 132 km Time taken = (Distance)/(Speed) Time taken by the passenger train = 132/x hrs Time taken by the express train = 132/(x + 11) hrs â‡’ 132 Ã— 11 = x(x + 11) â‡’ x2 + 11x â€“ 1452 = 0 â‡’ x2 + 44x â€“ 33x â€“ 1452 = 0 â‡’ x(x + 44) â€“ 33(x + 44) = 0 â‡’ (x + 44)(x â€“ 33) = 0 â‡’ (x + 44) = 0 or (x â€“ 33) = 0 âˆ´ x = â€“44 or x = 33 Since speed cannot be negative, x = 33 Thus the sped of passenger train is 33 km/hr and speed of express train is 44 km/hr.

Agam Gupta

Let the speed of passenger train be x km/hr Hence speed of express train = (x +11) km/hr Distance travelled by both the trains = 132 km Time taken = (Distance)/(Speed) Time taken by the passenger train = 132/x hrs Time taken by the express train = 132/(x + 11) hrs â‡’ï¿½132 Ã— 11 = x(x + 11) â‡’ï¿½x2ï¿½+ 11x â€“ 1452 = 0 â‡’ï¿½x2ï¿½+ 44x â€“ 33x â€“ 1452 = 0 â‡’ï¿½x(x + 44) â€“ 33(x + 44) = 0 â‡’ï¿½(x + 44)(x â€“ 33) = 0 â‡’ï¿½(x + 44) = 0 or (x â€“ 33) = 0 âˆ´ x = â€“44 or x = 33 Since speed cannot be negative, x = 33 Thus the sped of passenger train is 33 km/hr and speed of express train is 44 km/hr.
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