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Gajaanan Muley

Nov 3, 2013

An express train takes 1 hour less than a passenger train

An express train takes 1 hour less than a passenger train to travel 132 km/hr between Mysore and Bangalore.If the average speed of the express train is 11 km/hr more than that of passenger train,form an equation to find the average speed of the express train.

Answers(2)

Answer

Kishore Kumar

Let the speed of passenger train be x km/hr
Hence speed of express train = (x +11) km/hr
Distance travelled by both the trains = 132 km
Time taken = (Distance)/(Speed)
Time taken by the passenger train = 132/x hrs
Time taken by the express train = 132/(x + 11) hrs

⇒ 132 × 11 = x(x + 11)
⇒ x2 + 11x – 1452 = 0
⇒ x2 + 44x – 33x – 1452 = 0
⇒ x(x + 44) – 33(x + 44) = 0
⇒ (x + 44)(x – 33) = 0
⇒ (x + 44) = 0 or (x – 33) = 0
∴ x = –44 or x = 33
Since speed cannot be negative, x = 33
Thus the sped of passenger train is 33 km/hr and speed of express train is 44 km/hr.
 

Agam Gupta

Let the speed of passenger train be x km/hr
Hence speed of express train = (x +11) km/hr
Distance travelled by both the trains = 132 km
Time taken = (Distance)/(Speed)
Time taken by the passenger train = 132/x hrs
Time taken by the express train = 132/(x + 11) hrs

⇒�132 × 11 = x(x + 11)
⇒�x2�+ 11x – 1452 = 0
⇒�x2�+ 44x – 33x – 1452 = 0
⇒�x(x + 44) – 33(x + 44) = 0
⇒�(x + 44)(x – 33) = 0
⇒�(x + 44) = 0 or (x – 33) = 0
∴ x = –44 or x = 33
Since speed cannot be negative, x = 33
Thus the sped of passenger train is 33 km/hr and speed of express train is 44 km/hr.
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