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Sujamma

Mar 19, 2018

Electrochemistry

From the following molar conductivities at infinite dilution ,calculate molar conductivities for NH4OH:
a)molar conductivities for Ba(OH)2 =457.6, BaCl2=240.6 and NH4Cl=129.8 ohm^-1cm^2mol^-1

Answers(2)

Answer

Hhh

Electro chemistry

Agam Gupta

\lambda _m^\infty Ba(OH)2 = \lambda ^o_B_a_^2^+ + 2\lambda ^o_O_H_^-..(i)

\lambda _m^\infty (BaCl2 )= \lambda ^o_B_a_^2^+ + 2\lambda ^o_C_l_^-...(ii)

\lambda _m^\infty (NH4Cl) = \lambda ^o_N_H_4^+ + \lambda ^o_C_l_^-..(iii)

\because \lambda _m^\infty f (NH4OH) = \lambda ^o_N_H_4^++\lambda ^o_O_H_^-

= 1/2 eq. (i) + eq (iii) -1/2 eq (ii)

= \frac{1}{2}\times 457.6+129.8-\frac{1}{2}\times 240.6

= 238.3 ohm-1 cm2 mol-1

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