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Neemit bagh

Jul 12, 2014

Find the dimensions of constant a and b occurig in van der Waal's equation . [p+a/v^{2}][v-b]=RT

Janhavi Govinda rao

(P + a/V^{2}) (V - b) = RT

P is pressure, V is volume and T is temperature.

[P] = [F/A] = [MLT^{ âˆ’2}/L^{2}] = [ML^{âˆ’1}T^{ âˆ’2}]

[V] = [L^{3}]

We cannot add or subtract quantities of different dimensions. Therefore

[P] = [a/V^{2}] â‡’ [a] = [PV^{2}] = [ML^{âˆ’1}T^{ âˆ’2} L^{6}] = [M L^{5} T^{ âˆ’2}]

âˆ´ [a] = [M L^{5} T^{ âˆ’2}]

Similarly,

[b] = [V] = [L^{3}]

P is pressure, V is volume and T is temperature.

[P] = [F/A] = [MLT

[V] = [L

We cannot add or subtract quantities of different dimensions. Therefore

[P] = [a/V

âˆ´ [a] = [M L

Similarly,

[b] = [V] = [L

Syeda

Answer.

(P + a/V^{2}) (V - b) = RT

P is pressure, V is volume and T is temperature.

[P] = [F/A] = [MLT^{ âˆ’2}/L^{2}] = [ML^{âˆ’1}T^{ âˆ’2}]

[V] = [L^{3}]

We cannot add or subtract quantities of different dimensions. Therefore

[P] = [a/V^{2}] â‡’ [a] = [PV^{2}] = [ML^{âˆ’1}T^{ âˆ’2} L^{6}] = [M L^{5} T^{ âˆ’2}]

âˆ´ [a] = [M L^{5} T^{ âˆ’2}]

Similarly,

[b] = [V] = [L^{3}]

(P + a/V

P is pressure, V is volume and T is temperature.

[P] = [F/A] = [MLT

[V] = [L

We cannot add or subtract quantities of different dimensions. Therefore

[P] = [a/V

âˆ´ [a] = [M L

Similarly,

[b] = [V] = [L