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Asked by Mehnaaz

Nov 12, 2014

Find the smallest 4 digit number which is divisible by 18, 24, 32.

Ramesh

Member since Apr 1, 2014

Sol:

LCM of 18, 24 and 32:

18 = 2 x 3 x 3

24 = 2 x 2 x 2 x 3

32 = 2 x 2 x 2 x 2 x 2

LCM = 2 x 2 x 2 x 2 x 2 x 3 x 3 = 288

The smallest four digit number that is divisible by 288:

288 x 3 = 864

288 x 4 = 1152

Since 288 is divisible by 18, 24 and 32, 1152 is also divisible by all these numbers.

Therefore, 1152 is the smallest four digit number divisible by 18, 24 and 32.

Syeda

Member since Jan 25, 2017

Answer.

LCM of 18, 24 and 32:

18 = 2 x 3 x 3

24 = 2 x 2 x 2 x 3

32 = 2 x 2 x 2 x 2 x 2

LCM = 2 x 2 x 2 x 2 x 2 x 3 x 3 = 288

The smallest four digit number that is divisible by 288:

288 x 3 = 864

288 x 4 = 1152

Since 288 is divisible by 18, 24 and 32, 1152 is also divisible by all these numbers.

Therefore, 1152 is the smallest four digit number divisible by 18, 24 and 32.

Ashok K Singh

For this, first we need to find the LCM of the given numbers.

LCM of 18, 24 and 32 is 288.

Now, we have to get the multiple of 288 which also should be the samllest 4-digit number.

288 x 1 = 288 (a three digit number)

288 x 2 = 576 (a three digit number)

288 x 3 = 864 (a three digit number)

288 x 4 = 1152 (a four digit number)

So, 1152 is the required number.

LCM of 18, 24 and 32 is 288.

Now, we have to get the multiple of 288 which also should be the samllest 4-digit number.

288 x 1 = 288 (a three digit number)

288 x 2 = 576 (a three digit number)

288 x 3 = 864 (a three digit number)

288 x 4 = 1152 (a four digit number)

So, 1152 is the required number.

Surabhi

9,999

Kejal

The number which is given we have to a the in which tables that goes the ?which u gave and is 1152 so it is very easy