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Tushara

Apr 18, 2014

# Number of electrons present in 1.4 grams of Nitrogen gas

Calculate number of electrons present in 1.4 grams of Nitrogen gas.

Ans: Number of moles in the given weight of Nitrogen gas. Number of moles = Given weight/molecular weight = 1.4/28 =0.05 moles 1 mole of Nitrogen contains Avogadro number (6.023*1023) of Nitrogen molecules. 0.05 moles of Nitrogen contains = 0.05*6.023*1023 = 3.011*1022 molecules 1 molecule of Nitrogen contains 14 electrons 3.011*1022 molecules contains = 3.011*1022*14 = 42.154*1022 = 4.215*1023 number of electrons

Akshita Chotia

N2 weight = 28g 28g of N2 contains 7 electron 1g will contain 7/28 electron 1.4g will contain 7/28*1.4 =0.35 electron

Syeda

Answer. Number of moles in the given weight of Nitrogen gas. Number of moles = Given weight/molecular weight = 1.4/28 =0.05 moles 1 mole of Nitrogen contains Avogadro number (6.023*1023) of Nitrogen molecules. 0.05 moles of Nitrogen contains = 0.05*6.023*1023 = 3.011*1022 molecules 1 molecule of Nitrogen contains 14 electrons 3.011*1022 molecules contains = 3.011*1022*14 = 42.154*1022 = 4.215*1023 number of electrons SME Approved

 so u calculate the grams into moles then into number of particles. then u multiply that by the number of electrons in nitrogen

Jaimin

4.21Ãƒâ€”10Ãƒâ€”23
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