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Tushara

Apr 18, 2014

Number of electrons present in 1.4 grams of Nitrogen gas

Calculate number of electrons present in 1.4 grams of Nitrogen gas. 

Answers(5)

Answer

Satyanarayana Prasad

Ans: Number of moles in the given weight of Nitrogen gas.
Number of moles = Given weight/molecular weight
= 1.4/28
=0.05 moles
1 mole of Nitrogen contains Avogadro number (6.023*1023) of Nitrogen molecules.
0.05 moles of Nitrogen contains = 0.05*6.023*1023
= 3.011*1022 molecules
1 molecule of Nitrogen contains 14 electrons
3.011*1022 molecules contains = 3.011*1022*14
= 42.154*1022
= 4.215*1023 number of electrons

Akshita Chotia

N2 weight = 28g
28g of N2 contains 7 electron
1g will contain 7/28 electron
1.4g will contain 7/28*1.4 =0.35 electron

Syeda

Answer.

Number of moles in the given weight of Nitrogen gas.
Number of moles = Given weight/molecular weight
= 1.4/28
=0.05 moles
1 mole of Nitrogen contains Avogadro number (6.023*1023) of Nitrogen molecules.
0.05 moles of Nitrogen contains = 0.05*6.023*1023
= 3.011*1022 molecules
1 molecule of Nitrogen contains 14 electrons
3.011*1022 molecules contains = 3.011*1022*14
= 42.154*1022
= 4.215*1023 number of electrons

Amarthya Pradeep

 so u calculate the grams into moles then into number of particles. then u multiply that by the number of electrons in nitrogen 

Jaimin

4.21×10×23
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