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Dhruv Son

Mar 9, 2015

# The length of longest pole that can be put in a room of dimensions (10m x 10m x 5m) is _________.

The length of longest pole that can be put in a room of dimensions (10m x 10m x 5m) is _________.

Ramesh

Length of the longest pole that can be put in a room = Length of the diagonal inside the room Length of the diagonal = $âˆš\left($$\sqrt{{\text{l}}^{\text{2}}}$  + b2   + h2) = âˆš(102 + 102 + 52) = âˆš(100 + 100 + 25) = âˆš225 = 15 Hence, the length of the longest pole that can be put in the room is 15 m.$\sqrt{{\text{}}^{}}$

Member since Apr 1, 2017

$\fn_cm \\Solution:\\ Given\ dimensions\ are\\ Length\ (l)=10m\\ Breadth\ (b)=10m\\ Height\ (h)=5m\\\\ Imagine\ we\ can\ place\ the\ longest\ length\ of\ rod ,\ along\ the\ diagonal\ of\ the\ room\ (cuboid)\\\\ We\ have,\\\\ Daignal(d))=\sqrt{l^2+b^2+h^2}\\\\ \Rightarrow d=\sqrt{10^2+10^2+5^2}\\\\ \Rightarrow d=\sqrt{100+100+25}\\\\ \Rightarrow d=\sqrt{225}\\\\ \Rightarrow d=15m\\\\ \therefore The\ longest\ length\ of\ rod\ that\ can\ be\ placed\ in\ a\ room=15m$
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