The parallelograms are on the same base and between the same parallels.
Area of a Parallelogram = b × h
In both parallelograms:
• The bases are equal.
• The heights are equal.
Area of parallelogram ABCD = Area of parallelogram ABGH.
Parallelograms on the same base and between the same parallels are equal in area.
Prove that the area of the triangle is equal to half the area of the parallelogram, if they are on the same base and are between the same parallels.
Δ ABP and parallelogram ABCD are on same base AB and between the same parallels AB and PC.
To Prove: ar (ΔABP) =1/2 ar ( ||gm ABCD)
Construction: Draw BQ || AP
ar ( ||gm ABQP) = ar ( || gm ABCD (Parallelograms on the same base and between the same parallels are equal in area.)
Δ ABP ≅ Δ BQP
ar (Δ ABP) = ar (Δ BQP)
ar (Δ ABP) = (½) ar (|| gm ABQP)
ar (Δ ABP) = (½) ar (|| gm ABCD).
Recall that sum of angles of a polygon = (2n - 4) × 90°
Here number of sides, n = 9
Hence the sum of angles of the given pol...
Length = 21 cm
Breadth = 9 cm
width = 8 cm
Surface Area of tin box (excluding lid)
= 2(bh+hl) + lb...
root3/4 a suare
Perimeter of triangle = ( a + b + c) = (26 + 28 + 30) cm = 84 cm
s = 84 cm
s = 42 cm,a =...
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